Question 1 : Fetch the similar items from two sets.
Given Sets:
set1 = {10,20,30,40,50}
set2 = {20,30,50,60,70}Expected Output:
{50, 20, 30}[bg_collapse view=”button-red” color=”#ffffff” icon=”eye” expand_text=”Show Answer” collapse_text=”Hide Answer”]
For this, we will use the intersection() method.
set1 = {10,20,30,40,50}
set2 = {20,30,50,60,70}
new_set = set1.intersection(set2)
print(new_set)Output:
{50, 20, 30}[/bg_collapse]
Question 2 : Fetch the Unique items from two sets.
Given Sets:
set1 = {10,20}
set2 = {20,30}Expected Output:
{10, 20, 30}[bg_collapse view=”button-red” color=”#ffffff” icon=”eye” expand_text=”Show Answer” collapse_text=”Hide Answer”]
For this, we will use the union() method.
set1 = {10,20}
set2 = {20,30}
new_set = set1.union(set2)
print(new_set)Output:
{10, 20, 30}[/bg_collapse]
Question 3 : Update the set1 with the items that are unique to set1 only (means that do not exist in set2).
Given Sets:
set1 = {10,20,40}
set2 = {20,30,50}Expected Output:
{40, 10}[bg_collapse view=”button-red” color=”#ffffff” icon=”eye” expand_text=”Show Answer” collapse_text=”Hide Answer”]
For this, we will use the union() method.
set1 = {10,20,40}
set2 = {20,30,50}
set1.difference_update(set2)
print(set1)Output:
{40, 10}[/bg_collapse]
Question 4 : Fetch the uncommon elements from set1 and set2.
Given Sets:
set1 = {10, 20, 30, 40}
set2 = {20, 30, 40, 50}Expected Output:
{10, 50}[bg_collapse view=”button-red” color=”#ffffff” icon=”eye” expand_text=”Show Answer” collapse_text=”Hide Answer”]
For this, we will use the symmetric_difference_update() method.
set1 = {10, 20, 30, 40}
set2 = {20, 30, 40, 50}
set1.symmetric_difference_update(set2)
print(set1)Output:
{10, 50}[/bg_collapse]
Question 5 : How to check if there are any common elements in two sets. If yes, print them.
Given Sets:
set1 = {10, 20, 30, 40}
set2 = {20, 30, 40, 50}Expected Output:
Here is the list of common elements:
{40, 20, 30}[bg_collapse view=”button-red” color=”#ffffff” icon=”eye” expand_text=”Show Answer” collapse_text=”Hide Answer”]
For this, we will use the isdisjoint() method and intersection() method.
set1 = {10, 20, 30, 40}
set2 = {20, 30, 40, 50}
if set1.isdisjoint(set2):
print("Nothing in Common")
else:
print("Here is the list of common elements:")
print(set1.intersection(set2))Output:
Here is the list of common elements:
{40, 20, 30}[/bg_collapse]
Question 6 : From the given set of names, separate the names that start with j and t and create two new sets.
Given Set:
names = {"Jack", "John", "Tim", "Thomas", "Jim", "Tom" }Expected Output:
{'Jim', 'John', 'Jack'}
{'Tim', 'Thomas', 'Tom'[bg_collapse view=”button-red” color=”#ffffff” icon=”eye” expand_text=”Show Answer” collapse_text=”Hide Answer”]
Solution:
names = {"Jack", "John", "Tim", "Thomas", "Jim", "Tom" }
j_names = set()
t_names = set()
for n in names:
if n.startswith("J"):
j_names.add(n)
if n.startswith("T"):
t_names.add(n)
print(j_names)
print(t_names)Output:
{'Jim', 'John', 'Jack'}
{'Tim', 'Thomas', 'Tom'}[/bg_collapse]
Question 7 : In Python, which operator is used to determine that if a set is the subset of another set?
[bg_collapse view=”button-red” color=”#ffffff” icon=”eye” expand_text=”Show Answer” collapse_text=”Hide Answer”]
Approach 1 : Using the issubset() method:
s1 = {1,2,3,4,5,6,7,8,9}
s2 = {1,2,3,4}
print(s2.issubset(s1)) #s2 is subset of s1
print(s1.issubset(s2)) #s1 is subset of s2Approach 2 : Using the < operator:
s1 = {1,2,3,4,5,6,7,8,9}
s2 = {1,2,3,4}
print(s2 < s1) #s2 is subset of s1
print(s1 < s2) #s1 is subset of s2Output:
True
False[/bg_collapse]
Question 8 : Create an empty “names” set and then add 4 names, rename 1 of them and then remove 2 names from the set.
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Solution:
my_set = set()
my_set.add("Steve")
my_set.add("Jeff")
my_set.add("Jack")
my_set.add("Elon")
print("Four elements are :", my_set)
my_set.remove("Steve")
my_set.add("Tim")
print("Elements after modifying one are :", my_set)
my_set.remove("Jeff")
my_set.remove("Elon")
print("Elements after removing two :", my_set)Output:
Four elements are : {'Jeff', 'Jack', 'Elon', 'Steve'}
Elements after modifying one are : {'Jeff', 'Jack', 'Elon', 'Tim'}
Elements after removing two : {'Jack', 'Tim'}[/bg_collapse]
Question 9 : Create a set of 10 random integers between 10 and 40. Now print the count of numbers less than 20 and remove numbers > 30 from the set.
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Solution:
import random
count = 0
s = set()
temp_set = set()
while len(s) < 10:
s.add(random.randint(10,40))
print("Original Set =", s)
for i in s:
if i < 20:
count = count + 1
if i <= 30:
temp_set.add(i)
s = temp_set
print("Items less than 20 =", count)
print("Set after deleting items =", s)Output:
Original Set = {32, 36, 38, 39, 40, 11, 16, 27, 28, 30}
Items less than 20 = 2
Set after deleting items = {11, 16, 27, 28, 30}[/bg_collapse]